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    Matrix Diagonalization

    Result

    (1 | 2 | 3 3 | 2 | 1 2 | 1 | 3) = S.J.S^(-1) where S = (1 | 1/7 (-13 - 9 sqrt(2)) | 1/7 (9 sqrt(2) - 13) 1 | 1/7 (5 + 11 sqrt(2)) | 1/7 (5 - 11 sqrt(2)) 1 | 1 | 1) J = (6 | 0 | 0 0 | -sqrt(2) | 0 0 | 0 | sqrt(2)) S^(-1) = (11/34 | 9/34 | 7/17 1/68 (-11 - sqrt(2)) | 1/68 (10 sqrt(2) - 9) | 1/68 (20 - 9 sqrt(2)) 1/68 (sqrt(2) - 11) | 1/68 (-9 - 10 sqrt(2)) | 1/68 (20 + 9 sqrt(2)))

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