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    Adjoint

    Result

    (1 | 3 | 1 2 | 2 | 2 3 | 1 | 3)

    Jordan decomposition

    (1 | 3 | 1 2 | 2 | 2 3 | 1 | 3) = S.J.S^(-1) where S = (-1 | 1/2 | 5 0 | -1/2 | 6 1 | 0 | 7) J = (0 | 1 | 0 0 | 0 | 0 0 | 0 | 6) S^(-1) = (-7/18 | -7/18 | 11/18 2/3 | -4/3 | 2/3 1/18 | 1/18 | 1/18)

    Dimensions

    3 (rows) × 3 (columns)

    Matrix plot

    Matrix plot

    Transpose

    (1 | 2 | 3 3 | 2 | 1 1 | 2 | 3)

    Trace

    6

    Determinant

    0

    Matrix rank

    2

    Nullity

    1

    Characteristic polynomial

    6 λ^2 - λ^3

    Eigenvalues

    λ_1 = 6

    λ_2 = 0

    Eigenvectors

    v_1 = (5, 6, 7)

    v_2 = (-1, 0, 1)

    Condition number

    ∞

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