(1 | 3 | 2 2 | 2 | 1 3 | 1 | 3)

3 (rows) × 3 (columns)

(1 | 2 | 3 3 | 2 | 1 2 | 1 | 3)

6

-12

1/12(-5 | 7 | 1 3 | 3 | -3 4 | -8 | 4)

-λ^3 + 6 λ^2 + 2 λ - 12

λ_1 = 6

λ_2 = -sqrt(2)

λ_3 = sqrt(2)

v_1 = (11, 9, 14)

v_2 = (1/2 (-2 - sqrt(2)), 1/sqrt(2), 1)

v_3 = (1/2 (-2 + sqrt(2)), -1/sqrt(2), 1)

(1 | 3 | 2 2 | 2 | 1 3 | 1 | 3) = P.D.P^(-1) where P≈(11 | -1.70711 | -0.292893 9 | 0.707107 | -0.707107 14 | 1 | 1) D≈(6 | 0 | 0 0 | -1.41421 | 0 0 | 0 | 1.41421) P^(-1)≈(0.0294118 | 0.0294118 | 0.0294118 -0.393058 | 0.314049 | 0.106942 -0.018707 | -0.725814 | 0.481293)

7.58333