Ellipses: Definitions and Examples

Ellipses: Definitions, Formulas, & Examples

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    Introduction:

    Ellipses are one of the most important and frequently studied shapes in mathematics. In this article, we will explore the definition of an ellipse, its properties, and various formulas related to it. We will also provide numerous examples to illustrate the concepts discussed.

    Definition:

    An ellipse is a geometric figure that is obtained by cutting a circular cone with a plane that is not parallel to its base. It can also be defined as a set of points in a plane, the sum of whose distances from two fixed points (the foci) is constant. In other words, an ellipse is the locus of points whose distance from two fixed points (the foci) is constant.

    Properties:

    Some of the important properties of an ellipse are:

    • The major axis of an ellipse is the longest diameter, and the minor axis is the shortest diameter.
    • The distance between the foci is equal to the length of the major axis.
    • The distance between the center and either focus is called the eccentricity, denoted by e. The value of e is always less than 1.
    • The perimeter of an ellipse is given by the formula: P = 4aE(e), where a is the length of the semi-major axis, E(e) is the complete elliptic integral of the second kind, and e is the eccentricity.
    • The area of an ellipse is given by the formula: A = ?ab, where a and b are the lengths of the semi-major and semi-minor axes, respectively.

    Formulas:

    Some of the important formulas related to an ellipse are:

    • The equation of an ellipse centered at the origin is given by: x^2/a^2 + y^2/b^2 = 1, where a and b are the lengths of the semi-major and semi-minor axes, respectively.
    • The equation of an ellipse with center (h, k) is given by: (x – h)^2/a^2 + (y – k)^2/b^2 = 1.
    • The eccentricity of an ellipse is given by the formula: e = ?(1 – b^2/a^2), where a and b are the lengths of the semi-major and semi-minor axes, respectively.
    • The focus-directrix property of an ellipse states that a ray emanating from one focus and striking the ellipse will reflect off the ellipse and pass through the other focus.
    • The standard form of the equation of the tangent to an ellipse at a point (x, y) is given by: x(x – a)/a^2 + y(y – b)/b^2 = 1.

    Examples:

    • Find the equation of the ellipse with center (2, -3), semi-major axis 5, and semi-minor axis 3.

    Solution: Using the formula for the equation of an ellipse with center (h, k), we have: (x – 2)^2/25 + (y + 3)^2/9 = 1.

    • Find the eccentricity of the ellipse whose equation is x^2/16 + y^2/9 = 1.

    Solution: Comparing the given equation with the standard form of the equation of an ellipse, we have a = 4 and b = 3. Using the formula for eccentricity, we get: e = ?(1 – 9/16) = ?(7/16) = ?7/4.

    • Find the foci and eccentricity of the ellipse with equation 9x^2 + 16y^2 = 144.

    Solution: Dividing both sides of the equation by 144, we get: x^2/16 + y

    Substituting a = 4 and b = 3 in the equation of the ellipse, we get: x^2/16 + y^2/9 = 1. Therefore, the foci of the ellipse are located at the points (±c, 0), where c is given by the formula c = ?(a^2 – b^2). Substituting a = 4 and b = 3, we get c = ?7. Hence, the foci are located at (±?7, 0). Using the formula for eccentricity, we get: e = ?(1 – 9/16) = ?7/4.

    • Find the equation of the tangent to the ellipse x^2/25 + y^2/16 = 1 at the point (3, 4).

    Solution: Substituting x = 3 and y = 4 in the equation of the ellipse, we get: 9/25 + 16/16 = 1. Therefore, the given point lies on the ellipse. The equation of the tangent to the ellipse at the point (3, 4) is given by: x(x – a)/a^2 + y(y – b)/b^2 = 1, where a = 5 and b = 4. Substituting the values of a, b, x, and y, we get: 3(x – 5)/25 + 4(y – 4)/16 = 1. Simplifying, we get: 3x/25 + 4y/16 = 1, which is the required equation of the tangent.

    • Find the area of the ellipse with equation x^2/9 + y^2/4 = 1.

    Solution: Comparing the given equation with the standard form of the equation of an ellipse, we have a = 3 and b = 2. Using the formula for the area of an ellipse, we get: A = ?ab = ?(3)(2) = 6?.

    • A searchlight is placed at one focus of an ellipse with semi-major axis 10 and semi-minor axis 8. Find the equation of the ellipse.

    Solution: Let the focus be located at the point (c, 0). Since the distance between the foci is equal to the length of the major axis, the other focus is located at the point (-c, 0), where c = ?(a^2 – b^2) = ?(100 – 64) = ?36 = 6. Therefore, the equation of the ellipse is given by: x^2/100 + y^2/64 = 1.

    • Find the equation of the ellipse whose foci are located at (-1, 2) and (5, 2), and whose major axis is of length 10.

    Solution: Since the foci are located on the x-axis and the distance between them is 6, the center of the ellipse is located at the point (2, 2). Therefore, the major axis is parallel to the x-axis and its length is 10. Hence, the semi-major axis is 5. Using the formula for the distance between a point and a line, we can find the length of the semi-minor axis. The distance between the point (-1, 2) and the x-axis is 2, and the distance between the point (5, 2) and the x-axis is also 2. Therefore, the length of the semi-minor axis is 2. The equation of the ellipse is given by: (x – 2)^2/25 + y^2/4 = 1.

    • Find the equation of the ellipse whose foci are located at (±3, 0) and whose minor axis has length 8.

    Solution: Since the foci are located on the x-axis and the distance between them is 6, the center of the ellipse is located at the point (0, 0). Therefore, the semi-major axis is equal to half the length of the major axis, which is 4. Using the formula for the distance between two points, we get: ?[(x – 3)^2 + y^2] + ?[(x + 3)^2 + y^2] = 2a, where a is the semi-major axis. Substituting a = 4 and simplifying, we get: x^2/16 + y^2/9 = 1, which is the required equation of the ellipse.

    • Find the length of the latus rectum of the ellipse x^2/16 + y^2/9 = 1.

    Solution: The length of the latus rectum of an ellipse is given by 2b^2/a, where a and b are the semi-major and semi-minor axes, respectively. Substituting a = 4 and b = 3, we get: 2(3)^2/4 = 9/2. Therefore, the length of the latus rectum is 9/2.

    • Find the distance between the center and a vertex of the ellipse x^2/25 + y^2/16 = 1.

    Solution: The distance between the center and a vertex of an ellipse is equal to the semi-major axis. Comparing the given equation with the standard form of the equation of an ellipse, we have a = 5. Therefore, the distance between the center and a vertex of the ellipse is 5.

    FAQs:

    • What is an ellipse?

    An ellipse is a type of conic section, which is the locus of all points in a plane such that the sum of their distances from two fixed points (called foci) is constant.

    • What is the standard form of the equation of an ellipse?

    The standard form of the equation of an ellipse is given by (x – h)^2/a^2 + (y – k)^2/b^2 = 1, where (h, k) is the center of the ellipse, a is the semi-major axis, and b is the semi-minor axis.

    • What is the eccentricity of an ellipse?

    The eccentricity of an ellipse is a measure of how “stretched out” or “flattened” the ellipse is. It is defined as the ratio of the distance between the foci to the length of the major axis.

    • How do you find the foci of an ellipse?

    The foci of an ellipse are located at the points (±c, 0), where c is given by the formula c = ?(a^2 – b^2), where a and b are the lengths of the semi-major and semi-minor axes, respectively.

    • What is the difference between an ellipse and a circle?

    A circle is a special case of an ellipse in which the two foci coincide at the center of the circle, and the length of the major and minor axes are equal.

    Quiz:

    1. What is the standard form of the equation of an ellipse? a) (x – h)^2/a^2 + (y – k)^2/b^2 = 1 b) x^2/a^2 + y^2/b^2 = 1 c) x^2/a^
    2. What is the definition of an ellipse? a) The locus of all points in a plane such that the sum of their distances from two fixed points (called foci) is constant. b) The locus of all points in a plane such that their distance from a fixed point (called the focus) is proportional to their distance from a fixed line (called the directrix). c) The locus of all points in a plane such that their distance from a fixed point (called the center) is constant.
    3. What is the eccentricity of an ellipse? a) The ratio of the distance between the foci to the length of the major axis. b) The ratio of the length of the major axis to the length of the minor axis. c) The ratio of the distance between the center and a vertex to the length of the minor axis.
    4. What is the equation of the ellipse whose foci are located at (±2, 0) and whose minor axis has length 6? a) x^2/9 + y^2/4 = 1 b) x^2/4 + y^2/9 = 1 c) x^2/36 + y^2/16 = 1
    5. What is the length of the latus rectum of the ellipse x^2/9 + y^2/4 = 1? a) 2/3 b) 4/3 c) 6/5
    6. What is the distance between the center and a vertex of the ellipse x^2/16 + y^2/9 = 1? a) 3 b) 4 c) 5
    7. What is the equation of the ellipse with center (3, -2), major axis length 8, and minor axis length 6? a) (x – 3)^2/16 + (y + 2)^2/9 = 1 b) (x – 3)^2/9 + (y + 2)^2/16 = 1 c) (x – 3)^2/64 + (y + 2)^2/36 = 1
    8. What is the length of the semi-minor axis of the ellipse x^2/36 + y^2/16 = 1? a) 2 b) 3 c) 4
    9. What is the eccentricity of the ellipse x^2/25 + y^2/16 = 1? a) 3/5 b) 4/5 c) 5/4
    10. What is the distance between the foci of the ellipse x^2/36 + y^2/16 = 1? a) ?5 b) ?10 c) ?13

    Answers:

    1. a
    2. a
    3. a
    4. a
    5. b
    6. c
    7. b
    8. b
    9. c
    10. c

    Conclusion:

    In conclusion, an ellipse is a fascinating geometric shape that has numerous applications in science, engineering, and mathematics. It is the locus of all points in a plane such that the sum of their distances from two fixed points (called foci) is constant. The standard form of the equation of an ellipse is (x – h)^2/a^2 + (y – k)^2/b^2 = 1, where (h, k) is the center of the ellipse, and a and b are the lengths of the semi-major and semi-minor axes, respectively. We can use the properties of an ellipse to find its foci, vertices, and other important characteristics.

    Moreover, we can use the properties of an ellipse to solve real-world problems. For example, engineers use ellipses to design antennas and reflectors for satellite communication. Scientists use ellipses to model the orbit of planets, comets, and asteroids in space. Mathematicians use ellipses to study the geometry of conic sections and to develop mathematical models for economic and social phenomena.

    We hope this article has provided a clear understanding of the ellipse and its properties. By mastering the concepts and formulas presented here, you can confidently solve problems involving ellipses and apply them to a wide range of fields.

     

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    Ellipses:

    Scientific name

    Venustaconcha ellipsiformis

    Taxonomy

    kingdom | Animalia (animals)
phylum | Mollusca (molluscs)
class | Bivalvia (molluscs, scallops, clams, oysters and mussels)
order | Unionoida (freshwater mussels)
family | Unionidae
genus | Venustaconcha
species | Venustaconcha ellipsiformis (ellipse)

    Biological properties

    maximum recorded length | 3 inches

    duration of pregnancy | 43 weeks (human: 40 wk)

    (typical values, except where otherwise noted)

    Genome information

     | sequence length | genes | RNA structures | proteins
mitochondrion | 17174 | 13 | 24 | 13
(partial chromosome sequence coverage)

    Image

    Image

    Species authority

    Conrad, 1836

    Other members of genus Venustaconcha

    Venustaconcha pleasi (bleedingtooth mussel) | Venustaconcha pleasii (bleedingtooth mussel)

    Taxonomic network

    Taxonomic network

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